1-x-0.6x^2=0

Solution for 1-x-0.6x^2=0 equation:

1-x-0.6x^2=0

We add all the numbers together, and all the variables

-0.6x^2-1x+1=0

a = -0.6; b = -1; c = +1;
Δ = b2-4ac
Δ = -12-4·(-0.6)·1
Δ = 3.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{3.4}}{2*-0.6}=\frac{1-\sqrt{3.4}}{-1.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{3.4}}{2*-0.6}=\frac{1+\sqrt{3.4}}{-1.2}
$